[ R_{cond} = \frac{\ln(0.06/0.05)}{2\pi \cdot 15} = \frac{\ln(1.2)}{94.2478} = \frac{0.1823}{94.2478} = 0.001934 , \text{m·K/W} ]
Heat transfer is the backbone of countless engineering applications—from designing a CPU cooler to building a power plant. But theory can only take you so far. To truly understand conduction, convection, and radiation, you have to work through the numbers.
For steady-state 1D conduction without heat generation: